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| 1 | +// SPDX-License-Identifier: MIT |
| 2 | +import { test, expect } from '@playwright/test'; |
| 3 | +import { sendPromptAndWait } from './test-helpers'; |
| 4 | + |
| 5 | +test('regenerate: re-running keeps 1 user / 1 assistant in the conversation', async ({ |
| 6 | + page, |
| 7 | +}) => { |
| 8 | + // Reuse the smoke 'say hi briefly' fixture — aimock returns the same |
| 9 | + // response on regenerate; the invariant we care about is the count. |
| 10 | + await sendPromptAndWait(page, 'say hi briefly'); |
| 11 | + |
| 12 | + const userMessages = page.locator('chat-message[data-role="user"]'); |
| 13 | + const assistantMessages = page.locator('chat-message[data-role="assistant"]'); |
| 14 | + await expect(userMessages).toHaveCount(1); |
| 15 | + await expect(assistantMessages).toHaveCount(1); |
| 16 | + |
| 17 | + // Click Regenerate on the assistant message (aria-label is the durable hook). |
| 18 | + await page.getByRole('button', { name: 'Regenerate response' }).first().click(); |
| 19 | + |
| 20 | + // Wait for the regenerated assistant turn to finalize (data-streaming flips |
| 21 | + // back to true then false). We can't reuse sendPromptAndWait here because |
| 22 | + // there's no fresh prompt to send — instead poll until exactly one |
| 23 | + // finalized assistant is present and the count holds at 1/1. |
| 24 | + await expect |
| 25 | + .poll( |
| 26 | + async () => |
| 27 | + page |
| 28 | + .locator('chat-message[data-role="assistant"][data-streaming="false"]') |
| 29 | + .count(), |
| 30 | + { timeout: 45_000 }, |
| 31 | + ) |
| 32 | + .toBeGreaterThan(0); |
| 33 | + |
| 34 | + // Single-turn invariant: after regenerate, conversation stays at 1u/1a |
| 35 | + // (the assistant message is replaced in place, not appended). |
| 36 | + await expect(userMessages).toHaveCount(1); |
| 37 | + await expect(assistantMessages).toHaveCount(1); |
| 38 | +}); |
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