From e286390869a936f98bc32ea619d53e3e2f6be095 Mon Sep 17 00:00:00 2001
From: graceRodiguez <grace.Rodriguez6@upr.edu>
Date: Mon, 15 Feb 2016 23:09:20 -0400
Subject: [PATCH] Added my application for codetrotters.

---
 graceRodriguezApplication.py | 113 +++++++++++++++++++++++++++++++++++
 1 file changed, 113 insertions(+)
 create mode 100644 graceRodriguezApplication.py

diff --git a/graceRodriguezApplication.py b/graceRodriguezApplication.py
new file mode 100644
index 0000000..91476e0
--- /dev/null
+++ b/graceRodriguezApplication.py
@@ -0,0 +1,113 @@
+############################################################################
+# Author: Grace M. Rodriguez Gomez\
+# Codetrotters Challenge
+# 02/15/2016
+# Description: Given an input of an integer from 0 to 999,999,9999
+# the script proceeds to translate it into words depending on its units.
+############################################################################
+
+#List of the numbers words depending on units.
+ones = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
+teens = [ "ten" ,"eleven" ,"twelve", "thirteen" , "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]
+tenths = [ "ten","twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]
+
+
+def int_to_words(num):
+	hundreds = ""
+	thousands = ""
+	millions = ""
+	finalString = ""
+	count = 0
+
+	#Iterate through the srping in reversed, this is done so the hundreds can be gotten first, the thousands
+	#second and the millions last 
+	for i in reversed(num):
+		count += 1
+		#The number is seperated to three parts each containing three digits each.
+		if count <= 3:
+			hundreds += i
+		elif count >3 and count <=6:
+			thousands += i
+		elif count > 6: 
+			millions += i
+
+	#Each part is reversed
+	hundreds = hundreds[::-1]
+	thousands = thousands[::-1]
+	millions = millions[::-1]
+	
+	#Depending if there are millions or thousands, enter the getWords function 
+	if len(millions) > 0:
+		#Add the resulting string from getWords and saved the corresponding words according to its units
+		finalString += getWords(millions) + " million "
+	if len(thousands) > 0:
+		finalString += getWords(thousands) + " thousand "
+	
+	hStr = getWords(hundreds)
+	
+	finalString += hStr
+
+	print finalString
+
+
+def getWords(wordParts):
+#This function is going to convert the segregated parts of the input number to words. 
+#Each part has a maximum of 3 digits and a minimum of 1.
+
+	numWords = ""
+
+	#If the length of the word part is only one, then it's just one unit, and it will be 
+	#search in the list of ones.
+	if len(wordParts) == 1:
+		numWords += ones[int(wordParts[0])-1]
+
+	#If the length of the word is two, then it will search either in the teens list if its
+	#first digit is 1 or in the tenths list if the first digit is bigger than 1.   
+	elif len(wordParts) == 2:
+		if int(wordParts[0]) == 1:
+			numWords += teens[int(wordParts[1])]
+		elif int(wordParts[0]) >= 2 and int(wordParts[1]) == 0:
+			numWords += tenths[int(wordParts[0])-1]
+		elif int(wordParts[0]) >= 2 and int(wordParts[1]) > 0: 
+			numWords += tenths[int(wordParts[0])-1] + "-" + ones[int(wordParts[1])-1]
+	
+	#If the length of the word is three, then there are a couple of cases than can happen.
+	elif len(wordParts) == 3:
+		#If the first digit is not 0, look for the digit in the ones list and add a "hundred" 
+		if int(wordParts[0]) != 0:
+			numWords = ones[int(wordParts[0])%10-1] + " hundred "
+		#Second digit is 1, look for the digit in teens list
+		if int(wordParts[1]) == 1:
+			numWords += teens[int(wordParts[2])]
+		#Second digit is bigger than on, look in tenth list
+		elif int(wordParts[1]) >= 2 and int(wordParts[2]) == 0:
+			numWords += tenths[int(wordParts[1])-1]
+		#If the third digit isn't cero, add a "-" and the corresponding word for the ones list
+		elif int(wordParts[1]) >= 2 and int(wordParts[2]) > 0: 
+			numWords += tenths[int(wordParts[1])-1] + "-" + ones[int(wordParts[2])-1]
+		#If 2nd digit is 0 and the 3rd >= 1, add the corresponding word 
+		elif int(wordParts[1]) == 0 and int(wordParts[2]) >= 1:
+			numWords += ones[int(wordParts[2])-1]
+	return numWords
+	
+def main():
+	#Get input. Make sure it's an integer and in the accepted range.
+	while True:
+		try:
+			num = int(raw_input("Please choose a number from 0 to 999999999 without comas. "))		
+			if (num > 999999999):
+				print "Number exceeds limits, please put a number from 0 to 999,999,999. "
+				num = int(raw_input(""))
+			if num == 0:
+				print "zero"
+			else:
+				int_to_words(str(num))
+				command = raw_input("Would you like to convert another integer? y/n  ")
+				if command == "n":
+					break	
+		except ValueError:
+			print "Oops! Input should be an integer. Try again."			
+
+
+if __name__ == "__main__":
+    main()
\ No newline at end of file