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Copy path106-ConstructBinaryTreeFromInorderAndPostorderTraversal.java
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57 lines (48 loc) · 1.45 KB
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public TreeNode buildTree(int[] inorder, int[] postorder) {
HashMap<Integer, Integer> map = new HashMap<>();
for(int i = 0; i < inorder.length; i++) {
map.put(inorder[i], i);
}
return construct(postorder.length-1, 0, inorder.length-1, postorder, map);
}
public TreeNode construct(
int postStart,
int inStart,
int inEnd,
int[] postorder,
Map<Integer, Integer> map){
if(postStart<0 || inStart>inEnd) return null;
int val = postorder[postStart];
TreeNode root = new TreeNode(val);
int inIndex = map.get(val);
int rightSize = inEnd-inIndex;
root.left = construct(postStart-(rightSize)-1, inStart, inIndex-1, postorder, map);
root.right = construct(postStart-1, inIndex+1, inEnd, postorder, map);
return root;
}
}