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LevelOrderTraversal.py
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63 lines (47 loc) · 1.65 KB
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#https://leetcode.com/problems/binary-tree-level-order-traversal/#/description
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Node(object):
def __init__(self,node,level):
self.node = node
self.level = level
class Solution(object):
def __init__(self):
self.array = []
self.level_counter = 0
self.result = []
self.levelq = []
def queue(self,node):
self.array.append(node)
def isNotEmpty(self):
return self.array
def popValue(self):
value = self.array[0]
del self.array[0]
return value
def levelOrder(self, root):
"""
:type root: TreeNode
:rtype: List[List[int]]
"""
if not root:
return self.result
self.queue(Node(root,0))
while self.isNotEmpty():
bigNode = self.popValue()
if bigNode.level > self.level_counter:
self.level_counter = bigNode.level
self.result.append(self.levelq[:])
self.levelq[:] = []
self.levelq.append(bigNode.node.val)
if bigNode.node.left :
self.queue(Node(bigNode.node.left, bigNode.level + 1))
if bigNode.node.right :
self.queue(Node(bigNode.node.right, bigNode.level + 1))
if self.levelq:
self.result.append(self.levelq[:])
return self.result