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0516.Longest_Palindromic_Subsequence.py
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46 lines (34 loc) · 1.17 KB
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"""
Given a string s, find the longest palindromic subsequence's length in s.
A subsequence is a sequence that can be derived from another sequence by deleting some or no elements without changing the order of the remaining elements.
Example 1:
Input: s = "bbbab"
Output: 4
Explanation: One possible longest palindromic subsequence is "bbbb".
Example 2:
Input: s = "cbbd"
Output: 2
Explanation: One possible longest palindromic subsequence is "bb".
Constraints:
1 <= s.length <= 1000
s consists only of lowercase English letters.
"""
"""
1.dp[i][j] represent 字符串s[i:j]最长回文子序列的长度 包括i, j
2.递推关系
if i==j dp[i][j] = 2 + dp[i+1][j-1] if
if i!=j dp[i][j] = max(dp[i+1][j], dp[i][j-1])
"""
class Solution:
def longestPalindromeSubseq(self, s: str) -> int:
n = len(s)
dp = [[0]*n for _ in range(n)]
for i in range(n):
dp[i][i] = 1
for i in range(n-2, -1, -1):
for j in range(i+1, n):
if s[i] == s[j]:
dp[i][j] = 2 + dp[i+1][j-1]
else:
dp[i][j] = max(dp[i+1][j], dp[i][j-1])
return dp[0][n-1]