-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathDay1.cpp
More file actions
45 lines (37 loc) · 1.52 KB
/
Day1.cpp
File metadata and controls
45 lines (37 loc) · 1.52 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
/* Question
1143. Longest Common Subsequence
Given two strings text1 and text2, return the length of their longest common subsequence. If there is no common subsequence, return 0.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
For example, "ace" is a subsequence of "abcde".
A common subsequence of two strings is a subsequence that is common to both strings.
Example 1:
Input: text1 = "abcde", text2 = "ace"
Output: 3
Explanation: The longest common subsequence is "ace" and its length is 3.
Example 2:
Input: text1 = "abc", text2 = "abc"
Output: 3
Explanation: The longest common subsequence is "abc" and its length is 3.
Example 3:
Input: text1 = "abc", text2 = "def"
Output: 0
Explanation: There is no such common subsequence, so the result is 0.
Constraints:
1 <= text1.length, text2.length <= 1000
text1 and text2 consist of only lowercase English characters.*/
//Solution
class Solution {
public:
int longestCommonSubsequence(string text1, string text2) {
const int m = text1.length();
const int n = text2.length();
// dp[i][j] := the length of LCS(text1[0..i), text2[0..j))
vector<vector<int>> dp(m + 1, vector<int>(n + 1));
for (int i = 0; i < m; ++i)
for (int j = 0; j < n; ++j)
dp[i + 1][j + 1] = text1[i] == text2[j]
? 1 + dp[i][j]
: max(dp[i][j + 1], dp[i + 1][j]);
return dp[m][n];
}
};