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CountingInversionProblem.java
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91 lines (71 loc) · 1.71 KB
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import java.util.Scanner;
public class CountingInversionProblem {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the no. of elements : ");
int n = sc.nextInt();
System.out.println("Enter " + n + " integers");
int[] numbers = new int[n];
for (int i = 0; i < n; i++) {
numbers[i] = sc.nextInt();
}
System.out.println("Given Array is ");
printArray(numbers);
int totalInversions = countingInversionUsingMergeSort(numbers, 0, n - 1);
System.out.println("No. Of Inversions are : " + totalInversions);
}
static void printArray(int arr[]) {
int n = arr.length;
for (int i = 0; i < n; ++i)
System.out.print(arr[i] + " ");
System.out.println();
}
static int countingInversionUsingMergeSort(int arr[], int l, int r) {
int inversionCount = 0;
if (l < r) {
int m = (l + r) / 2;
inversionCount = countingInversionUsingMergeSort(arr, l, m);
inversionCount = inversionCount + countingInversionUsingMergeSort(arr, m + 1, r);
inversionCount = inversionCount + merge(arr, l, m, r);
}
return inversionCount;
}
static int merge(int arr[], int l, int m, int r) {
int count = 0;
int n1 = m - l + 1;
int n2 = r - m;
int L[] = new int[n1];
int R[] = new int[n2];
for (int i = 0; i < n1; i++) {
L[i] = arr[l + i];
}
for (int i = 0; i < n2; i++) {
R[i] = arr[m + 1 + i];
}
int i = 0, j = 0;
int k = l;
while (i < n1 && j < n2) {
if (L[i] <= R[j]) {
arr[k] = L[i];
i++;
}
else {
arr[k] = R[j];
count = count + (m + 1) - (l + i);
j++;
}
k++;
}
while (i < n1) {
arr[k] = L[i];
i++;
k++;
}
while (j < n2) {
arr[k] = R[j];
j++;
k++;
}
return count;
}
}