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Solution.py
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66 lines (58 loc) · 1.81 KB
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from typing import List
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
if not root:
return []
result = []
search = [root]
while len(search) > 0:
size = len(search)
target = []
for _ in range(size):
s = search.pop(0)
target.append(s.val)
if s.left:
search.append(s.left)
if s.right:
search.append(s.right)
result.append(target)
return result
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
if not root:
return []
def bfs(nodeList: List[TreeNode], result: List[int]):
if len(nodeList) == 0:
return
arrs = []
next_arrs = []
for node in nodeList:
arrs.append(node.val)
if node.left:
next_arrs.append(node.left)
if node.right:
next_arrs.append(node.right)
result.append(arrs)
bfs(next_arrs, result)
result = []
bfs([root], result)
return result
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
res = []
def dfs(node: TreeNode, deep: int, res):
if not node:
return
if deep == len(res):
res.append([])
res[deep].append(node.val)
dfs(node.left, deep + 1, res)
dfs(node.right, deep + 1, res)
dfs(root, 0, res)
return res