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PalindromeNumber.java
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52 lines (47 loc) · 1.29 KB
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package easy;
/**
* Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward.
* <p>
* 判断一个整数是否是回文数。回文数是指正序(从左向右)和倒序(从右向左)读都是一样的整数。
* <p>
* Created by kaming on 2018/7/14.
*/
public class PalindromeNumber {
/**
* Example 1:
* Input: 121
* Output: true
*
* Example 2:
*
* Input: -121
* Output: false
* Explanation: From left to right, it reads -121. From right to left,
*
* Example 3:
*
* Input: 10
* Output: false
* Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
*
*/
public static void main(String[] args) {
boolean exp1 = isPalindrome(121);
System.out.println(exp1);
boolean exp2 = isPalindrome(-121);
System.out.println(exp2);
boolean exp3 = isPalindrome(10);
System.out.println(exp3);
}
private static boolean isPalindrome(int x) {
if (x < 0 || (x % 10 == 0 && x != 0)) {
return false;
}
int rev = 0;
while (x > rev) {
rev = rev * 10 + x % 10;
x /= 10;
}
return rev == x || (x == rev / 10);
}
}