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Here are the |
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Could you please rebase this? |
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I rebased this PR for you. |
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| if verbose > 0 | ||
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| @info @sprintf "%6s %8s %8s %8s %7s %7s %8s %7s %7s %7s %7s %1s" "outer" "inner" "f(x)" "h(x)" "√ξ1" "√ξ" "ρ" "Δ" "‖x‖" "‖s‖" "1/ν" "TR" | ||
| @info @sprintf "%6s %8s %8s %8s %7s %7s %8s %7s %7s %7s %7s %1s" "outer" "inner" "f(x)" "h(x)" "√(ξ1/ν)" "√(ξ/ν)" "ρ" "Δ" "‖x‖" "‖s‖" "1/ν" "TR" |
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Compute
The other solvers don't compute or output
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I was stuck on this when I was rebasing on Friday. It doesn't make sense to me to only do
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| subsolver_options.ϵa = k == 1 ? 1.0e-5 : max(ϵ_subsolver, min(1e-2, sqrt_ξ1_νInv)) | ||
| subsolver_options.ϵa = k == 1 ? 1.0e-5 : max(ϵ_subsolver, min(1e-2, sqrt_ξ1_νInv) * ξ1) |
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@geoffroyleconte I reinstated this because it disappeared in ac255073a980ee340c02d7dff568dc0f2a07d265. It's not clear which produces the best results.
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It was intended, and this choice is mentioned in the section numerical results of indef-pg.
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| σmax = opnorm(Jk) | ||
| νInv = (1 + θ) * (σmax^2 + σk) # ‖J'J + σₖ I‖ = ‖J‖² + σₖ | ||
| ν = 1 / νInv |
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Why do we bother doing this? Why not just set ν directly?
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