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[서희] 유형1: INNER JOIN #3
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,7 @@ | ||
| -- [문제] 각 sale_id에 해당하는 제품 이름, 판매 연도, 판매 가격을 출력하시오. (INNER JOIN 사용) | ||
| -- 테이블: sales, product | ||
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| SELECT product.product_name, sales.year, sales.price | ||
| FROM sales | ||
| INNER JOIN product | ||
| ON sales.product_id = product.product_id; |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,12 @@ | ||
| -- [문제] 2025년 2월에 100개 이상 주문한 제품 이름과 수량을 출력하시오. (INNER JOIN 사용) | ||
| -- 테이블: products, orders | ||
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| SELECT p.product_name, o.unit | ||
| FROM products AS p | ||
| INNER JOIN ( | ||
| SELECT product_id, SUM(unit) AS unit | ||
| FROM orders | ||
| WHERE DATE_FORMAT(order_date, '%Y-%m') = '2025-02' | ||
| GROUP BY product_id | ||
| HAVING SUM(unit) >= 100 | ||
| ) AS o ON p.product_id = o.product_id; | ||
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,10 @@ | ||
| -- [문제] 관리자 보다 높은 급여를 받는 직원 이름을 출력하시오. (SELF JOIN, INNER JOIN 사용) | ||
| -- 테이블: employee | ||
|
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| SELECT e1.name | ||
| FROM employee AS e1 | ||
| INNER JOIN employee AS e2 | ||
| ON e1.manager_id = e2.emp_id | ||
| WHERE e1.salary > e2.salary; | ||
|
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| -- 피드백: 가독성을 위해 직원 테이블은 e, 관리자 테이블은 m으로 별칭을 정하는 것이 더 명확할 것 같다. |
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