complete

[sundeep4sandy]

No description provided.

[super30admin]

Search inside a Rotated Sorted Array (33searchInRotatedSortedArray.js)

Your solution is excellent and meets all the problem requirements. Here are a few points to consider for improvement:

1. Midpoint Calculation: You used (left + right) >>> 1 which is a good way to avoid integer overflow in JavaScript. However, given the constraints (array length up to 5000), using Math.floor((left + right) / 2) is also safe and might be more readable for some. Your current approach is efficient and correct.

2. Edge Cases: Your solution handles edge cases well (e.g., single element, target not present). However, it's always good to test with a few more edge cases, such as when the array is not rotated, or when the target is the first or last element.

3. Comments: The comments are helpful, but you could make them slightly more descriptive. For example, instead of "Left half is sorted", you could say "If the left part [left, mid] is sorted", and similarly for the right part.

4. Consistency: The condition in the right sorted part uses target > nums[mid] which is the same as nums[mid] < target. Both are fine, but for consistency with the left part (where you used target >= nums[left]), you might consider using the same style.

Overall, this is a very good implementation. Keep up the good work!

VERDICT: PASS

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Search Inside a Sorted Array whose Length is unknown (702searchInASortedArrayOfUnknownSize)

Your solution is excellent and follows the expected approach. You correctly identified the need to first find a range where the target might be located by doubling the high index until it exceeds the target. Then you performed a standard binary search within that range.

Strengths:

• Correct use of exponential growth to determine the search bounds.
• Proper implementation of binary search with clear variable names.
• Use of >>> to avoid overflow in midpoint calculation, which is particularly important in JavaScript since it uses 32-bit numbers for bitwise operations.
• Efficient time and space complexity.

Areas for improvement:

• While the code is correct, consider adding a comment explaining why you use >>> (zero-fill right shift) for those who might not be familiar with its purpose in integer division.
• Ensure that the initial expansion step does not run indefinitely by relying on the constraint that the array reader returns 2^31 - 1 for out-of-bound indices. This is already handled correctly.

Overall, this is a solid implementation.

VERDICT: PASS

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Search a 2D Matrix (74searchA2DMatrix.js)

The student's solution is excellent. It correctly implements the binary search algorithm for the 2D matrix problem. The code is efficient, both in time and space, and is written in a clear and concise manner. The use of the unsigned right shift operator for integer division by 2 is a good touch in JavaScript to avoid floating point issues in the midpoint calculation.

One minor point: while (lo + hi) >>> 1 is safe for integers (even when lo + hi might be large, but within the 32-bit integer range), note that in JavaScript, numbers are 64-bit floats. However, for the constraints given (m, n up to 100, so total elements up to 10000), lo + hi will be at most 9999, which is well within the 32-bit integer range. So it's safe.

Alternatively, some might prefer Math.floor((lo + hi) / 2) for clarity, but the bitwise shift is common and efficient.

Overall, the solution is correct and meets all requirements.

VERDICT: PASS