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@megharaykar
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@super30admin
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Your solution is well-structured and correctly implements the binary search approach to solve the problem in O(log n) time. The code is readable and your comments are helpful. Here are some points to consider:

  1. The condition if nums[low] <= nums[high] is correctly placed inside the loop to handle the case when the current segment is sorted.

  2. The condition for checking if mid is the minimum element by comparing with its neighbors is correctly implemented with bounds checking.

  3. The logic for moving left or right based on whether the left part is sorted is correct.

However, there is one minor improvement: in the condition for moving, you have if nums[mid] >= nums[low], which is correct. But note that when the array has duplicates, this might cause issues. However, the problem states that all integers are unique, so it's safe.

Overall, your solution is correct and efficient. Good job!

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