S30 FAANMG Problem #9 | Find the First and Last Position of an Elemen…

[sandy7907]

…t in given Sorted Array

[super30admin]

Strengths:

• The solution correctly handles edge cases, such as an empty array or when the target is not within the range of the array.
• The binary search functions are implemented correctly, with proper conditions to check for the first and last occurrences.
• The code is clean and well-commented, making it easy to understand.

Areas for Improvement:

• The initial condition to check if the target is outside the array range is efficient but might be redundant because the binary search would handle it anyway. However, it is a good optimization to avoid unnecessary searches.
• In the getFirstOccurance function, the condition if(mid == low || nums[mid-1] != nums[mid]) is correct, but note that when mid == low, accessing nums[mid-1] would cause an index out of bounds error. However, since the condition checks mid == low first (using short-circuit OR), it avoids the error. This is acceptable, but it's important to be cautious. Alternatively, you could write it as if (mid == 0 || nums[mid-1] != target) for clarity, similar to the reference solution.
• Similarly, in getLastOccurance, the condition if(mid == high || nums[mid+1] != nums[mid]) is correct, but using target instead of nums[mid] might be more consistent, though it is equivalent since nums[mid] == target at that point.

Overall, the solution is excellent and meets all requirements.