Add countZero.py to count the number of zeros in an integer array#125
Add countZero.py to count the number of zeros in an integer array#125x0lg0n merged 1 commit intox0lg0n:mainfrom
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Reviewer's GuideIntroduces a standalone Python script countZero.py that provides a count_zeros utility, robust input parsing (with optional leading length token), a CLI entrypoint with error handling and a self-test fallback when no valid input is supplied. Sequence diagram for CLI execution and self-test fallbacksequenceDiagram
actor User
participant "main()"
participant "parse_input()"
participant "count_zeros()"
User->>"main()": Run script (stdin input)
"main()"->>"parse_input()": Parse stdin
alt Valid input
"main()"->>"count_zeros()": Count zeros in input array
"count_zeros()"-->>"main()": Return zero count
"main()"->>User: Print zero count
else Invalid/no input
"main()"->>User: Print error or demo message
"main()"->>"count_zeros()": Count zeros in demo array
"count_zeros()"-->>"main()": Return zero count
"main()"->>User: Print demo zero count
end
Class diagram for countZero.py functionsclassDiagram
class count_zeros {
+int count_zeros(iterable: Iterable[int])
}
class parse_input {
+list parse_input(stream)
}
class main {
+int main()
}
count_zeros <.. main : uses
parse_input <.. main : uses
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WalkthroughA new Python script Changes
Estimated code review effort🎯 2 (Simple) | ⏱️ ~8 minutes
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✅ Passed checks (2 passed)
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Hey there - I've reviewed your changes and they look great!
Prompt for AI Agents
Please address the comments from this code review:
## Individual Comments
### Comment 1
<location> `Python/countZero.py:36` </location>
<code_context>
+ return c
+
+
+def parse_input(stream) -> list:
+ """Parse input from a stream and return a list of integers.
+
</code_context>
<issue_to_address>
**suggestion:** Consider specifying a more precise return type than 'list'.
Annotating the return type as 'list[int]' will make the function's output clearer and assist static analysis tools in detecting type issues.
```suggestion
def parse_input(stream) -> list[int]:
```
</issue_to_address>
### Comment 2
<location> `Python/countZero.py:20` </location>
<code_context>
+import sys
+
+
+def count_zeros(iterable: Iterable[int]) -> int:
+ """Return the number of zeros in the given iterable of integers.
+
</code_context>
<issue_to_address>
**issue (complexity):** Consider simplifying the code by merging input parsing and zero counting into the main function using Python built-ins.
```suggestion
You can collapse `parse_input` and `count_zeros` into just a few lines in `main`, leveraging Python built-ins and removing the custom loop / error branches:
```python
def main() -> int:
tokens = sys.stdin.read().split()
if not tokens:
demo = [0, 1, 0, 2, 0, 3]
print("No input detected — running demo array:", demo)
print("Zero count:", demo.count(0))
return 0
# parse ints, drop leading “count” if it matches remaining length
nums = list(map(int, tokens))
if len(nums) > 1 and nums[0] == len(nums) - 1:
nums = nums[1:]
print(nums.count(0))
return 0
```
This:
- Eliminates the separate `parse_input` + exception handling (the `map(int,…)` will raise if invalid).
- Removes the manual `for`-loop in `count_zeros` in favor of `.count(0)`.
- Keeps the demo fallback intact.
```
</issue_to_address>
### Comment 3
<location> `Python/countZero.py:29-33` </location>
<code_context>
def count_zeros(iterable: Iterable[int]) -> int:
"""Return the number of zeros in the given iterable of integers.
Args:
iterable: An iterable of integers.
Returns:
The count of values equal to 0.
"""
c = 0
for x in iterable:
if x == 0:
c += 1
return c
</code_context>
<issue_to_address>
**suggestion (code-quality):** We've found these issues:
- Convert for loop into call to sum() ([`sum-comprehension`](https://docs.sourcery.ai/Reference/Default-Rules/refactorings/sum-comprehension/))
- Inline variable that is immediately returned ([`inline-immediately-returned-variable`](https://docs.sourcery.ai/Reference/Default-Rules/refactorings/inline-immediately-returned-variable/))
```suggestion
return sum(1 for x in iterable if x == 0)
```
</issue_to_address>
### Comment 4
<location> `Python/countZero.py:50-53` </location>
<code_context>
def parse_input(stream) -> list:
"""Parse input from a stream and return a list of integers.
Expected: first token may be n (ignored if present), remaining tokens are treated as numbers.
"""
data = stream.read().strip().split()
if not data:
return []
# If first token looks like the count and matches remaining length, skip it
try:
nums = [int(tok) for tok in data]
except ValueError:
raise
if len(nums) >= 2 and nums[0] == len(nums) - 1:
return nums[1:]
# Otherwise return all tokens
return nums
</code_context>
<issue_to_address>
**suggestion (code-quality):** We've found these issues:
- Lift code into else after jump in control flow ([`reintroduce-else`](https://docs.sourcery.ai/Reference/Default-Rules/refactorings/reintroduce-else/))
- Replace if statement with if expression ([`assign-if-exp`](https://docs.sourcery.ai/Reference/Default-Rules/refactorings/assign-if-exp/))
```suggestion
return nums[1:] if len(nums) >= 2 and nums[0] == len(nums) - 1 else nums
```
</issue_to_address>Help me be more useful! Please click 👍 or 👎 on each comment and I'll use the feedback to improve your reviews.
| return c | ||
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| def parse_input(stream) -> list: |
There was a problem hiding this comment.
suggestion: Consider specifying a more precise return type than 'list'.
Annotating the return type as 'list[int]' will make the function's output clearer and assist static analysis tools in detecting type issues.
| def parse_input(stream) -> list: | |
| def parse_input(stream) -> list[int]: |
| import sys | ||
|
|
||
|
|
||
| def count_zeros(iterable: Iterable[int]) -> int: |
There was a problem hiding this comment.
issue (complexity): Consider simplifying the code by merging input parsing and zero counting into the main function using Python built-ins.
| def count_zeros(iterable: Iterable[int]) -> int: | |
| You can collapse `parse_input` and `count_zeros` into just a few lines in `main`, leveraging Python built-ins and removing the custom loop / error branches: | |
| ```python | |
| def main() -> int: | |
| tokens = sys.stdin.read().split() | |
| if not tokens: | |
| demo = [0, 1, 0, 2, 0, 3] | |
| print("No input detected — running demo array:", demo) | |
| print("Zero count:", demo.count(0)) | |
| return 0 | |
| # parse ints, drop leading “count” if it matches remaining length | |
| nums = list(map(int, tokens)) | |
| if len(nums) > 1 and nums[0] == len(nums) - 1: | |
| nums = nums[1:] | |
| print(nums.count(0)) | |
| return 0 |
This:
- Eliminates the separate
parse_input+ exception handling (themap(int,…)will raise if invalid). - Removes the manual
for-loop incount_zerosin favor of.count(0). - Keeps the demo fallback intact.
| c = 0 | ||
| for x in iterable: | ||
| if x == 0: | ||
| c += 1 | ||
| return c |
There was a problem hiding this comment.
suggestion (code-quality): We've found these issues:
- Convert for loop into call to sum() (
sum-comprehension) - Inline variable that is immediately returned (
inline-immediately-returned-variable)
| c = 0 | |
| for x in iterable: | |
| if x == 0: | |
| c += 1 | |
| return c | |
| return sum(1 for x in iterable if x == 0) |
| if len(nums) >= 2 and nums[0] == len(nums) - 1: | ||
| return nums[1:] | ||
| # Otherwise return all tokens | ||
| return nums |
There was a problem hiding this comment.
suggestion (code-quality): We've found these issues:
- Lift code into else after jump in control flow (
reintroduce-else) - Replace if statement with if expression (
assign-if-exp)
| if len(nums) >= 2 and nums[0] == len(nums) - 1: | |
| return nums[1:] | |
| # Otherwise return all tokens | |
| return nums | |
| return nums[1:] if len(nums) >= 2 and nums[0] == len(nums) - 1 else nums |
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Actionable comments posted: 1
🧹 Nitpick comments (2)
Python/countZero.py (2)
20-33: Consider a more Pythonic implementation.The manual counter loop is correct but can be simplified using
sum()with a generator expression for improved readability.Apply this diff to refactor the function:
def count_zeros(iterable: Iterable[int]) -> int: """Return the number of zeros in the given iterable of integers. Args: iterable: An iterable of integers. Returns: The count of values equal to 0. """ - c = 0 - for x in iterable: - if x == 0: - c += 1 - return c + return sum(1 for x in iterable if x == 0)
56-71: Use specific exception handling.Catching the broad
Exceptiontype can mask unexpected errors and make debugging more difficult. Sinceparse_inputraisesValueErrorfor parsing failures, catch that specific exception instead.As per static analysis hints.
Apply this diff to use specific exception handling:
def main() -> int: try: arr = parse_input(sys.stdin) - except Exception: + except ValueError: print("Error: failed to parse input. Expected integers.") return 1
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Python/countZero.py
47-48: Remove exception handler; error is immediately re-raised
(TRY203)
59-59: Do not catch blind exception: Exception
(BLE001)
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🔇 Additional comments (1)
Python/countZero.py (1)
1-18: Excellent documentation!The module docstring clearly explains the purpose, input format, and fallback behavior. The imports are minimal and appropriate.
2 participants
Summary by Sourcery
Add a standalone Python script countZero.py to parse integer arrays from stdin and print the number of zero elements, with a self-test demo on invalid or missing input.
New Features:
Summary by CodeRabbit